brittanyharris12 brittanyharris12

23-03-2018
Mathematics

contestada

in triangle ABC, AB=90 in., BC=80 in., and angle B measures 50 degrees. What is the approximate perimeter of the triangle?

Respuesta :

calculista calculista

01-04-2018

we know that

the Law of Cosines established:
AC² = AB² + BC² - 2·AB·BC·cos(b)
Therefore
AC = √(90² + 80² - 2·90·80·cos(50)
=√5243.86
= 72.4 in

Now you can sum up all the sides in order to find the perimeter:
AB + BC + AC = 90 + 80 + 72.4 = 242.4 in

the answer is
242.4 in

Answer Link

keywuanaw keywuanaw

08-01-2021

Answer:

A. 242.4

Step-by-step explanation:

edge 2020

Answer Link

Otras preguntas

In 1870, which area of the country was more densely populated—the Northeast or the Southeast?

Most candidates are elected to office during ......... elections

whats used to mark interruptions in thought and brief summaries of content

Which of the following types of software is most applicable to the promotion of new products through advertising? A.Databases B. Spreadsheets C. Web design prog

If each parent carries one sickle cell allele, what are the chances that their child will have sickle cell anemia?

find the volume of 3, 8 and one third and 10 and 2 over 5

based on the reading upton sinclair would most likely agree that meatpacking companies

Can someone please help me?! It would be much appreciated:)

A rhombus has sides 10 cm long and an angle of 30°. Find the distance between a pair of opposite sides.

Which equation illustrates the additive inverse property? A. 2 + (-2) = 0 B. 2 × 0 = 0 C. -2 + 2 = 2 + (-2) D. 1 + 2 + 3 = 1 + (2 + 3)