The reaction between Na and Cl2 is as follows ; 2Na + Cl2 —> 2NaCl Stoichiometry of Na to NaCl is 2:2 Since Cl2 is provided in excess , Na is the limiting reactant. Therefore amount of product formed depends on amount of Na present . Mass of Na reacted = 2.3 g Number of Na moles reacted = 2.3 g/23 g/ mol = 0.1 mol Therefore number of NaCl moles produced = 0.1 mol The mass of NaCl produced = 0.1 mol x 58.5 g/mol = 5.85 g