mariaemijan mariaemijan

24-10-2017
Mathematics

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[tex] \frac{1 - sin {}^{2}x }{cos {}^{2}x - 1 } = - \cot {}^{2} x[/tex]

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LammettHash LammettHash

24-10-2017

[tex]\dfrac{1-\sin^2x}{\cos^2x-1}=\dfrac{\cos^2x}{-\sin^2x}=-\cot^2x[/tex]

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