Answer:
350 N
Explanation:
Since the instructor falls at constant velocity, his acceleration is zero. This implies that the net force acting in the [tex]y[/tex] direction is zero, as per Newton's Second Law: [tex]F_{net}=ma[/tex]
For the parachute instructor, weight acts downwards while the force by the parachutes act upwards. Since the net force in the [tex]y[/tex] direction is zero, the upward force by the parachutes must equal in magnitude to the weight of the parachute instructor acting downwards. Hence:
[tex]F_{net}=0\\\\2(F_{parachute})=Weight\\\\2(F_{parachute})=700\\\\F_{parachute}=350N[/tex]
