Respuesta :

nikvist

Answer:

Step-by-step explanation:

[tex]y=x^2,\quad P=(0,1)\\d^2=(x-x_p)^2+(y-y_p)^2=(x-0)^2+(y-1)^2=x^2+y^2-2y+1\\d^2=y^2-y+1\\(d^2)'=2y-1=0,\quad y=1/2\\d=\sqrt{y^2-y+1}=\sqrt{1/4-1/2+1}=\sqrt{3}/2[/tex]

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