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  • 24-08-2017
  • Mathematics
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Find three consecutive odd integers that the sum of the first, two times, the second, and three times the third is 70

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Аноним Аноним
  • 24-08-2017
Let the integers be x-2, x, x+2.

Given,

(x - 2) + 2x + 3(x + 2) = 70

x - 2 + 2x + 3x + 6 = 70

6x + 4 = 70

6x = 66

x = 11

Hence, the integers are 9, 11 and 13.
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