
Answer:
17.8 cm is the approximate length of its diagonal.
Step-by-step explanation:
Side of the square = l
Perimeter of the square = P = 56 cm
Perimeter of the square is the sum of all the sides of the square.
4a = 56 cm
[tex]4a=56 cm[/tex]
[tex]a=\frac{56}{4}=14 cm[/tex]
The length of the diagonal is given by: d
[tex]d^2=a^2+a^2[/tex] (Pythagoras theorem)
[tex]d=\sqrt{a^2+a^2}=\sqrt{2a^2}[/tex]
[tex]d=17.79 cm\approx 17.8 cm[/tex]
17.8 cm is the approximate length of its diagonal.