A pyramid composed of four equilateral triangles, called a tetrahedron, has a one-side length of 5 meters. What is its surface area? Round the answer to the nearest tenth.
The surface area of a regular tetrahedron is computed as the product of √3 and the square of the length of one side. The length given is 5 meters, by evaluating, we will have A = √3 (a²) = √3 (25) = 43.30. The answer is B.
