Relax

Respuesta :

we have the function

[tex]f(x)=(6x+1)^2[/tex]

Find out the derivative

[tex]\begin{gathered} f^{\prime}(x)=2(6x+1)^{2-1}(6x+1)^{\prime} \\ f^{\prime}(x)=2(6x+1)(6) \\ f^{\prime}(x)=12(6x+1) \\ f^{\prime}(x)=72x+12 \end{gathered}[/tex]

The answer is

f'(x)=72x+12