[tex]\begin{gathered} k=\frac{5}{9}(f-32)+273.15 \\ k=1.5 \\ 1.5=\frac{5}{9}(f-32)+273.15 \\ \text{Subtract 273.15 from both sides} \\ 1.5-273.15=\frac{5}{9}f-\frac{160}{9}\Rightarrow\frac{5}{9}f=1.5-273.15+\frac{160}{9} \\ \frac{5}{9}f=-253.872 \\ MultiplyBothSideBy,\frac{9}{5} \\ f=\frac{9}{5}\cdot(-253.872) \\ f=-456.97^{\circ} \end{gathered}[/tex]
The temperature of the object is -456.97 degrees
