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Respuesta :

[tex]\begin{gathered} x=\text{ Repeating decimal} \\ n=\text{ Number of repeating digits} \\ x=0.929292\text{ (1)} \\ \text{Multiply by 10}^n \\ 1000x=1000(0.929292) \\ 1000x=929.292 \\ \text{Subtract (1) from the last quation:} \\ 1000x-x=929.292-0.929292 \\ 999x=928.362708 \\ x=\frac{928.362708}{999}\approx\frac{92}{99} \\ \end{gathered}[/tex]

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