MaddonE499074 MaddonE499074

25-10-2022
Mathematics

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1+2 |x-1| less than or equal to 9

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KaelynneH388811 KaelynneH388811

25-10-2022

SOLUTION

The question is

[tex]1+2|x-1|\leq9[/tex]

Now let's solve. This becomes

[tex]\begin{gathered} 1+2|x-1|\leq9 \\ 2|x-1|\leq9-1 \\ 2|x-1|\leq8 \\ \\ \text{dividing both sides by x we have} \\ \\ |x-1|\leq4 \end{gathered}[/tex]

This becomes

[tex]\begin{gathered} x-1\leq4 \\ or \\ x-1\ge4 \end{gathered}[/tex]

So we have our x as

[tex]undefined[/tex]

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