
Respuesta :
The mass (in grams) of xenon in 3.541 g of the compound xenon tetrafluoride is 2.243 grams
Composition of xenon tetrafluoride, XeF₄
1 mole of XeF₄ contains the following:
- 1 mole of XeF₄ = 131.3 + (4 × 19) = 131.3 + 76 = 207.3 g
- 1 mole of XeF₄ contains 131.3 g of Xe
- 1 mole of XeF₄ contains 76 g of F
How to determine the mass of Xe in 3.541 g of XeF₄
The mass of Xe in 3.541 g XeF₄ can be obtained as illustrated below:
207.3 g of XeF₄ contains 131.3 g of Xe.
Therefore,
3.541 g of XeF₄ will contain = (3.541 g × 131.3 g) / 207.3 g = 2.243 g of Xe
Thus, 2.243 g of Xe is present in 3.541 g of xenon tetrafluoride, XeF₄
Learn more about mass composition:
https://brainly.com/question/22816432
#SPJ1