Equilibrium pressure of NO is 3.82 atm
What is the equilibrium pressure of NO?
The equilibrium pressure of NO is calculated from the equation of the reaction given below as follows:
N₂ + O₂ ⇄ 2 NO
Initial pressure of N₂ = 21.76 atm
Equilibrium pressure of N₂ = 21. 76 - x atm
Initial pressure of O₂ = 9.32 atm
Equilibrium pressure of O₂ = 9.32 - x atm
Initial pressure of NO = 0 atm
Equilibrium pressure of NO = 2x atm
Equilibrium constant = 0.050
0.050 = 2x²/(9.32 - x)(21. 76 - x)
2x² = 0.05(202.8 - 31.08x + x²)
2x² = 10.14 - 1.554x + 0.05x²
1.95x² + 1.554x - 10.14
x = 1.91 atm
2x = 3.82 atm
Therefore, equilibrium pressure of NO is 3.82 atm.
In conclusion, the equilibrium pressure is calculated from the equilibrium constant.
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