Answer: f(7/3)-h(-3)=22
Step-by-step explanation:
[tex]\displaystyle\\f(x)=3x-5\ \ \ \ h(x)=-x^2+3x-2\\\\f(\frac{7}{3})= 3*\frac{7}{3} -5\\\\f(\frac{7}{3})=7-5\\\\f(\frac{7}{3})=2\\\\h(-3)=-(-3)^2+3*(-3)-2\\\\h(-3)=-9-9-2\\\\h(-3)=-20\\\\f(\frac{7}{3})-h(-3)=2-(-20)\\\\ f(\frac{7}{3})-h(-3)=2+20\\\\f(\frac{7}{3})-h(-3)=22[/tex]
