The logarithmic form of 13^2=169 is [tex]\log_{13}(169) = 2[/tex]
How to determine the logarithmic form?
The equation is given as
13^2=169
Take the logarithm of both sides
log(13^2) = log(169)
This gives
2log(13) = log(169)
Divide both sides by log(13)
[tex]\log_{13}(169) = 2[/tex]
Hence, the logarithmic form of 13^2=169 is [tex]\log_{13}(169) = 2[/tex]
Read more about logarithmic forms at:
https://brainly.com/question/1870106
#SPJ1
