Answer:
p = -3
q = -10
Step-by-step explanation:
[tex]x^{2}+6x+19=x^{2}+6x+9+10[/tex]
[tex]\text{we know that} \ x^{2}+6x+9=\left (x+3)^2\right\ \text{ because it is a special product}[/tex]
[tex]\text therefore \ ,\ x^{2}+6x+19=(x + 3)^2+10[/tex]
[tex]\text therefore \ ,\ x^{2}+6x+19=0 \ means\ (x + 3)^2= -10\ means\ (x -\ - 3)^2= -10[/tex]
