The graph of a secant function shows no functional values on (−12, 12). The asymptotes of the function occur every π units.


Which function represents the secant function described?


f(x)=sec(x)+12

f(x)=12sec(x2)

f(x)=sec(x2)+12

f(x)=12sec(x)

Relax

Respuesta :

Answer:

f(x)=12sec (x)

Step-by-step explanation:

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