a runner joys 12km north than turs and runs 16km east in three hours.
a. what is his displacement
b. calculate his average speed
c. calculate his average including the direction ​

Relax

Respuesta :

Explanation:

a.displacement is vector quantity there fore

we combine the two direction

[tex] {c}^{2} = \sqrt{ {a}^{2} + {b}^{2} } [/tex]

[tex] {c}^{2 } = \sqrt{ {12}^{2} + {16}^{2} } [/tex]

[tex] {c}^{2} = \sqrt{400 } [/tex]

[tex]c = 20[/tex]

displacement is 20km to wards north

b:average speed

[tex]v = s \div t[/tex]

20/3=6.67

c: please type correctly