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A jet plane flying 600 m/s experiences an acceleration of 39.24 m/s² when pulling out of the circular section of a dive. What is the radius of curvature of this section of the dive?

The options are:

1.2 km
5.8 km
0.64 km
9.2 km
7.0 km

Relax

Respuesta :

Answer:

Explanation:

If we are to assume that the plane is at the bottom of a circular movement and just about to depart in level flight, then

(39.34 - 9.81) = 600²/R

R = 12,190.992211... m

Which is very close to the 1.2 km option

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