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Question : 14

let's solve for f :

  • [tex] \dfrac{1}{f} = \dfrac{1}{a} + \dfrac{1}{b} [/tex]

  • [tex] \dfrac{1}{f} = \dfrac{b + a}{ab} [/tex]

Taking reciprocal of both sides :

  • [tex]f = \dfrac{ab}{a + b} [/tex]

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