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25-03-2014
Mathematics

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What are the two consecutive number with a product of 121

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Аноним Аноним

25-03-2014

[tex]x(x+1)=121 \\ x^2+x-121=0 \\ \Delta=485[/tex]
Since [tex]\Delta[/tex] is not a perfect square, the solution is not integer. So there are no consecutive numbers really.

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