Answer:
Thus, the velocity at the time of strike is same as the velocity at the time of projection.
Explanation:
Let a projectile is projected vertically upwards with a speed of u and reaches to the maximum height H.
At maximum height , the speed is zero and then the projective comes back on the ground.
Use the third equation of motion
[tex]v^2 = u^2 + 2 g h \\\\0 = u^2 - 2 g H\\\\\u =\sqrt{2gH}[/tex]
Now let the velocity at the time of strike is v'.
Use third equation of motion, here initial velocity is zero.
[tex]v'^2 = 0 + 2 g H \\\\v = \sqrt{2gH}[/tex]
Thus, the velocity at the time of strike is same as the velocity at the time of projection.
