Answer:
[tex]x \leqslant 5[/tex]
Step-by-step explanation:
[tex]3(x - 3) \leqslant 2(x - 2)[/tex]
[tex]3x - 9 \leqslant 2x - 4[/tex]
[tex]3x - 2x \leqslant - 4 + 9[/tex]
Alternate form
x∈ 《-∞ , 5]
