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The volume of a sample of oxygen is 200.0 mL when the pressure is 3.00
atm and the temperature is 310 K. What is the new temperature if the
volume increases to 400.0 mL and the pressure decreases to 2.00 atm?*
322.3K
482.8 K
O 413.3K
686.0 K

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sqdancefan

9514 1404 393

Answer:

  C  413.3K

Step-by-step explanation:

Temperature is proportional to volume and pressure. Pressure has decreased by a factor of 2/3, and volume has increased by a factor of 400/200 = 2. So, the new temperature is ...

  (310 K)(2/3)(2) = 413 1/3 K ≈ 413.3 K

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