9514 1404 393
Answer:
(b) 6(a+1)
Step-by-step explanation:
Common factors are cancelled from numerator and denominator.
[tex]\displaystyle\frac{a^2-2a+1}{6}\div(a^2-1)=\frac{(a-1)^2}{6}\cdot\frac{1}{(a-1)(a+1)}\\\\=\frac{(a-1)(a-1)}{6(a-1)(a+1)}=\boxed{\frac{a-1}{6(a+1)}}[/tex]
The denominator of the result is 6(a+1).
