robertoa05 robertoa05

22-05-2021
Mathematics

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In the diagram below, AB = 15, DB = 6, BC = 8, and
mZB = 90°. What is the perimeter of triangle ADC?

In the diagram below AB 15 DB 6 BC 8 and mZB 90 What is the perimeter of triangle ADC class=

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mohamedruham35 mohamedruham35

22-05-2021

Answer:

B 36

Step-by-step explanation:

DC^2=6^2+8^2. AD=9cm DB=6cm

DC^2=36+64

DC^2=100

DC=√100

DC=10cm

AC^2=15^2+8^2

AC^2=225+64

AC^2=289

AC=√289

AC=17

P OF TRIANGLE ADC=10+9+17

=36cm

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