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The number 1 through 7 are written in separate slips of paper,and the slips are placed into a box.Then,4 of these slips are drawn at random.What is the probability that the drawn slips are 1,2,3 and 4 in that order

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Answer:

0.0011904

Step-by-step explanation:

Given that:

Number of slips = 7

Sample space = (1, 2, 3, 3, 5, 6, 7)

Numbwe of slips drawn = 4

Probability = required outcome / Total possible outcomes

Note ; selection is without replacement ;

P(drawing 1) = 1 /7

P(drawing 2) = 1 /6

P(drawing 3) = 1/5

P(drawing 4) = 1/4

1/7 * 1/6 * 1/5 * 1/4 = 0.0011904

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