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Captain Gabriela has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Daniel and his merciless band of thieves. The Captain has probability \dfrac{1}{2} 2 1 ​ start fraction, 1, divided by, 2, end fraction of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability \dfrac{1}{3} 3 1 ​ start fraction, 1, divided by, 3, end fraction. If both fire their cannons at the same time, what is the probability that both the Captain and the pirate miss?

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Answer:

1 /3

Step-by-step explanation:

Given that :

Probability that Captain hits pirate = 1/2 ;

P(captain hits) = 1/2

P(captain misses) = 1 - p(captain hits) = 1 - 1/2 = 1/2

Probability that Pirate hits Capitan = 1/3

P(pirate hits) = 1/2

P(pirate misses) = 1 - p(pirate hits) = 1 - 1/3 = 2/3

P(both pirate and captain miss)

P(captain miss) * P(pirate miss)

1/2 * 2/3

(1 *2) / (2*3)

= 2/6

= 1/3

Answer:

it's 1/10

Step-by-step explanation:

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