heyanswerme heyanswerme

25-02-2021
Mathematics

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in triangle PQR, Q=72 degrees, R=32 degrees and PR=12. find PQ

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reeserl reeserl

25-02-2021

Answer:

6.69 to the nearest hundredth

Step-by-step explanation:

Use the law of sines

Let x = PQ

[tex]\frac{sin 72}{12} = \frac{sin 32}{x}[/tex]

x sin 72 = 12 sin 32

[tex]x = \frac{12 sin 32}{sin 72}[/tex]

x = 6.69 to the nearest hundredth

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