jeancope78
contestada

The probability that Roberto throws a baseball in the strike zone on one pitch is 0.72. Roberto throws a baseball 3 times in a row.
A. Create a probability distribution for X, the number of times Roberto throws the baseball in the strike zone. Show how you obtained each probability. Round each probability to three decimal places.

Relax

Respuesta :

roo777x
I actually just finished this assignment: 

These are binomials with n = 3 and p = 0.72

P(X=0) = 3C0 (0.72^0)(0.28^3) = 0.022
P(X=1) = 3C0 (0.72^1)(0.28^2) = 0.169
P(X=2) = 3C0 (0.72^2)(0.28^1) = 0.435
P(X=3) = 3C0 (0.72^3)(0.28^0) = 0.373 

Notice how they all equal 1.

shristiparmar1221

This question is based on probability distribution. Therefore, the probability distribution for X are ,P(X=0) = 0.022 ,P(X=1) = 0.169, P(X=2) = 0.435 and P(X=3) = 0.373.

Given:

The probability that Roberto throws a baseball in the strike zone on one pitch is 0.72. Roberto throws a baseball 3 times in a row.

We need to determined the probability distribution for X ,the number of times Roberto throws the baseball in the strike zone.

According to the question,

By using the combination formula, we have to solve it,

It is given that n = 3 and p = 0.72.

Now calculating the P(X=0), we get,

[tex]P(X=0) = 3_{C_0}(0.72)^0(0.28)^3 \\P(X=0) = 0.022[/tex]

Now calculating the P(X=1), we get,

[tex]P(X=1) = 3_{C_0}(0.72)^1(0.28)^2 \\P(X = 1)= 0.169[/tex]

Now calculating the P(X=2), we get,

[tex]P(X=2) = 3_{C_0} (0.72)^2(0.28)^1 \\P(X=2) = 0.435[/tex]

Now calculating the P(X=3), we get,

[tex]P(X=3) = 3_{C_0} (0.72)^3(0.28)^0\\P(X=3) = 0.373[/tex]

Therefore, the probability distribution for X are ,P(X=0) = 0.022 ,P(X=1) = 0.169, P(X=2) = 0.435 and P(X=3) = 0.373.

For more details, prefer this link:

https://brainly.com/question/14210034

Otras preguntas