Given:
The equation is
[tex]8x-\dfrac{1}{3}y=67[/tex]
To find:
The intercepts of the line.
Solution:
We have,
[tex]8x-\dfrac{1}{3}y=67[/tex]
Putting x=0, we get
[tex]8(0)-\dfrac{1}{3}y=67[/tex]
[tex]0-\dfrac{1}{3}y=67[/tex]
[tex]-\dfrac{1}{3}y=67[/tex]
Multiply both sides by -3.
[tex]y=-201[/tex]
So, y-intercept is -201.
Putting y=0 in given equation, we get
[tex]8x-\dfrac{1}{3}(0)=67[/tex]
[tex]8x+0=67[/tex]
[tex]8x=67[/tex]
Divide both sides by 8.
[tex]x=\dfrac{67}{8}[/tex]
So, the x-intercept is [tex]x=\dfrac{67}{8}[/tex].
