Answer:
[tex]x=\frac{y-4}{1-i}[/tex]
[tex]y=4+(1-i)x[/tex]
Step-by-step explanation:
[tex]2y+ix=4+x-y[/tex]
solving for x
[tex]2y-y=4+x-ix\\\\y-4=(1-i)x\\\\x=\frac{y-4}{1-i}[/tex]
solving for y
[tex]2y+ix=4+x+y\\\\2y-y=4+x-ix\\\\y=4+(1-i)x[/tex]
or you could leave it as
[tex]y=4+x-ix[/tex]
