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Container A has 200 L of water, and is being filled at a rate of 6 liters per minute. Container B has 500 L of water, and is being drained at 6 liters per minute. How many minutes, m, will it take for the two containers to have the same amount of water?

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Answer:

25 minutes

Step-by-step explanation:

Container A : [tex]200 + 6x = y[/tex]

Container B: [tex]500 - 6x = y[/tex]

y = final volume of water

x = number of minutes

Final volume is same so:

[tex]200 + 6x = 500 - 6x\\12x = 300\\x = 25[/tex]

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