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25-10-2020
Mathematics

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Find the first five terms of the sequence an = 4n-6

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wegnerkolmp2741o wegnerkolmp2741o

25-10-2020

Answer:

-2,2,6,10,14

Step-by-step explanation:

an = 4n-6

Let n =1

a1 = 4*1-6=4-6 = -2

Let n =2

a2 = 4*2-6=8-6 = 2

Let n =3

a3 = 4*3-6=12-6 = 6

Let n =

a4 = 4*4-6=16-6 = 10

Let n =5

a5 = 4*5-6=20-6 = 14

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