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A satellite completes one revolution of a planet in almost exactly one hour. at the end of one hour, the satellite has traveled 2.0 × 107 meters and is only 10 meters away from its starting point. what is the numerical value of the satellite's average velocity after that one hour?

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nobillionaireNobley
Average velocity = total distance / time = 2.0 x 10^7 meters / 1hour = 2.0 x 10^7 m/hr

But 1000 m = 1 km
2.0 x 10^7 m/hr = 2.0 x 10^7 / 1000 = 2.0 x 10^4 km/hr

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