A bullet train traveling at 2.5m/s, takes 30 minutes to get to the station.
What was the train's acceleration in m/s^2?

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Muscardinus Muscardinus · Answer 1 · 2020-10-03T02:37:24+02:00

Answer:

[tex]a=-0.001388\ m/s^2[/tex]

Explanation:

Given that,

Initial speed of a train, u = 2.5 m/s

Finally, it reaches the station, v = 0 (at rest)

Time, t = 30 minutes = 1800 s

Acceleration is equal to the rate of change of velocity. So,

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0-2.5}{1800}\\\\a=-0.001388\ m/s^2[/tex]

So, its acceleration is [tex]0.001388\ m/s^2[/tex].

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