Answer:
g(1) = - 0.2
Step-by-step explanation:
To evaluate g(1), substitute x = 1 into g(x) , that is
g(1) = [tex]\frac{1^2-3}{10}[/tex] = [tex]\frac{1-3}{10}[/tex] = [tex]\frac{-2}{10}[/tex] = - 0.2
