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22-06-2020
Mathematics

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Given the following functions, find each of the values: f(x)=x2+3x−10 g(x)=x+5 (f+g)(−5)= (f−g)(3)= _

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22-06-2020

Answer:

(f+g)(-5)

(f+g)(x) = x²+3x-10+x+5

(f+g)(-5) = (-5)² + 3(-5)-10+(-5)+5

= 25-15-10-5+5 = 0

(f-g)(3)

(f-g)(x) = x²+3x-10 - (x+5)

= x²+3x-10-x-5

= x²+2x-15

(f-g)(3) = (3)²+2(3)-15

= 9+6-15 = 0

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