26-05-2020
Chemistry

contestada

what is the molarity of 3.0 L of solution containing 4.0 moles MgO

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enasyazzs enasyazzs

08-06-2020

Explanation:

v=3.0L (to calculate M, volume must be in L)

n=4.0 moles

M=n/v (formula molarity)

=4.0/3.0

=1.333M

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