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How many liters of 2.0 M HCl are required to exactly neutralize 1.5 L of 5.0 M NAOH?

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Answer:

3.25 L

Explanation:

A 2.0M solution of HCl will have 2 moles of HCl for each liter of solution. 1.5 liters of 5.0M NaOH has a total of 5*1.5=7.5 moles of NaOH. Therefore, you would need 7.5/2=3.25 liters of HCl. Hope this helps!