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In circle L, points E and F lie on the circle such that E, F and L are not collinear. If LE, LF and EF are drawn then which of the following must be true about LEF?
(1) It is a right triangle.
(2) it is and isosceles triangle.
(3) it is an equilateral triangle.
(4) it is an obtuse triangle.​

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Matheng

Answer:

option (2) it is and isosceles triangle.

Step-by-step explanation:

In circle L, points E and F lie on the circle such that E, F and L are not collinear

If LE, LF and EF are drawn

So, LE = EF = the radius of the circle L

So, LEF is an isosceles triangle.

The answer is option (2) it is and isosceles triangle.

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