An angle whose measure is –405° is in standard position. In what quadrant does the terminal side of the angle fall? Quadrant I Quadrant II Quadrant III Quadrant IV

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Answer:

(D)Quadrant IV

Step-by-step explanation:

Given the angle -405

[tex]-405^0=-360^0-45^0\\-45^0=-45^0+360=315^0[/tex]

Angle 315 degrees is in Quadrant IV [tex](270\leq x\leq 360)[/tex], therefore:

Angle -405 degrees is in Quadrant IV.

Answer:

405= Quadrant 1

-405= Quadrant IV

Step-by-step explanation:

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