goodlove8639 goodlove8639

22-04-2020
Chemistry

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Calculate the free energy δg at 25 ∘c for the nonstandard conditions at point c where the reaction quotient q is 3.58×109.

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ezeokechinonsohenry ezeokechinonsohenry

25-04-2020

Answer:

∆G=13.68kj

Explanation:

Free energy=?

Quotient q=3.58*10^9

Also ∆G signs-40.8

T=25°c ie 298°c.

Using this formula

∆Gf=∆G+RTinq

We're R =8.314= 0.008314kj

∆Gf= -40.8+0.008314*298in3.58*20^9

∆Gf=13.68kj

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