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There are 8 green, 10 purple, 6 red and 16 blue markers in a box. A marker is chosen,replaced and then another marker is chosen. Find the probability that neither marker is red.

Respuesta :

opudodennis

Answer:

0.98077

Step-by-step explanation:

-The probability of neither marker being red is equivalent to one minus the probability of both being red.

-The probability of both being red:

[tex]P(Red)=P_1(Red)\times P_2(Red)\\\\=\frac{6}{40}\times \frac{5}{39}\\\\=0.01923[/tex]

-The probability of neither being red is therefore calculated as:

[tex]P(No \ Red)=1-P(All \ Red)\\\\=1-0.01923\\\\=0.98077[/tex]

Hence, the probability of neither marker being red is 0.98077

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