Comic-strip Superhero meets an asteroid in outer space and hurls it at 800 m/s, as fast as a speeding bullet. The asteroid is a thousand times more massive than Superhero. In the strip, Superhero is seen at rest after the throw. Taking physics into account, what would be the speed of his recoil?

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priyankatutor priyankatutor · Answer 1 · 2022-01-10T07:11:05+01:00

The recoiling speed of the Superhero is - 0.8 m/s when the superhero hurls the asteroid at the speed of a bullet.

From the law of conservation of linear momentum, the momentum of the superhero and the asteroid will be equal.

Thus, From the law of conservation

[tex]m_1v_1 = -m_2v_2[/tex]

Where,

[tex]m_1[/tex] = mass of superhero

[tex]v_1[/tex] - speed of superhero = 800 m/s

[tex]m_2[/tex] - mass of asteroid = 1000m

[tex]v_2[/tex] = velocity of the asteroid

Put the values in the formula

[tex]m_1 \times 800 = -1000m \times v_2[/tex]

Mass [tex]m[/tex] will cancel each other,

[tex]v _2= \dfrac {800}{ -1000}\\\\v_2 = -0.8 \rm\; m/s[/tex]

Therefore, the recoiling speed of the Superhero is - 0.8 m/s.

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