Relax

Respuesta :

If ax=b and by=c, substituting you get that axy=c. Now, if cz=a, substituting again, axyz=a, from where it follows that xyz=1.

or

c = {b^y} = [(a^x)^y] = {a^(xy)}

a = [c^z] = [{a^(xy)}^z] = [a^(xyz)]

(a^1) = [a^(xyz)]

Therefore, (xyz) = 1.

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