The speed of the car at the top of the hill is 14m/s
Explanation:
given that
Initial velocity u of the car=0 m/s
The distance can be determined by finding out the difference between the elevation of the first slope and second slope.
elevation of the first slope=26 m
elevation of second slope=16m
distance s=26-16=10 m
acceleration due to gravity g=9.8 m/s2
speed of the car at the top of the hill can be determined by using the equation
[tex]v^2=u^2+2as\\v^2=0^2+2\times 9.8\times 10\\=196\\v=\sqrt{196} =14m/s[/tex]
speed of the car at the top of the hill is 14m/s
