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PbS(s)+4H2O2(aq)→PbSO4(s)+4H2O(l)PbS(s)+4H2O2(aq)→PbSO4(s)+4H2O(l) Express your answers as chemical symbols separated by a comma. Enter the oxidized element first.

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Answer:

Sulphur is oxidised

Hydrogen is reduced

Explanation:

Equation of the reaction

PbS(s) + 4H2O2(aq) → PbSO4(s) + 4H2O(l)

For Sulphur in PbS:

+2 + S = 0

S = -2

in PbSO4

+2 + S + (4 × -2) = 0

S = +6

Sulphur is oxidised.

For Hydrogen in H2O2:

2H + (2 × -2) = 0

H = +2

in H2O

H + (-2 × 1) = 0

H = +1

Hydrogen is reduced.

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