Answer:
Thus the dimensions to maximize the area is 30 by 60
Step-by-step explanation:
Let x= the length of the side perpendicular to the pen
and 120-2x= length of the side parallel to the shed
Area = x (120-2x) (1)
Area =120x - 2[tex]x^{2}[/tex]
The formula for the w-value of maximum is: -b/2a, thus our value will be:
-120/(-4) = 30
and substitue x = 30 into (1), we have: 120-2(30) =60
Thus the dimensions to maximize the area is 30 by 60
